Swiftでツリー曲線プログラム
概要
「Java人工知能プログラミング」
第1章 再帰処理と副問題への分割 – 1.2 フラクタルカーブ – ツリー曲線プログラム
をSwiftに変換。書籍はJavaです。
Playgroundで実行出来ます。
iPadのPlaygroundでも実行出来ます。
コード
import UIKit class Curve { var lastX:Double = 0.0 var lastY:Double = 0.0 func move(x:Double, y:Double) { lastX = x lastY = y } func forward(len:Double, angle:Double) { let x = lastX + len * cos(angle) let y = lastY + len * sin(angle) let uiBezierPath = UIBezierPath() uiBezierPath.move(to: CGPoint(x: lastX, y: lastY)) uiBezierPath.addLine(to : CGPoint(x: x, y: y)) uiBezierPath.stroke() move(x: x, y: y) } func draw(len:Double, angle:Double) { forward(len: len, angle: angle) } func strokeline(x1:Double, y1:Double, x2:Double, y2:Double) { let uiBezierPath = UIBezierPath() uiBezierPath.move(to: CGPoint(x: x1, y: y1)) uiBezierPath.addLine(to : CGPoint(x: x2, y: y2)) uiBezierPath.stroke() } } class Tree : Curve { func draw(n:Int, len:Double, angle:Double, sw:Int) { let x = lastX let y = lastY if n == 1 { forward(len: len, angle: angle) } else { let l = len / (2 / sqrt(2)) let a = .pi * 0.15 * Double(sw) forward(len: l * 0.33, angle: angle) draw(n: n - 1, len: l * 0.8, angle: angle - a, sw: 1) forward(len: l * 0.33, angle: angle) draw(n: n - 1, len: l * 0.7, angle: angle + a * 1.5, sw: -1) forward(len: l * 0.33, angle: angle) draw(n: n - 1, len: l * 0.6, angle: angle, sw: 1) } lastX = x lastY = y } } let size = CGSize(width: 600, height: 600) let point = CGPoint(x: 0, y: 0) CGRect(origin: point, size: size) let view = UIView(frame: CGRect(origin: point, size: size)) UIGraphicsBeginImageContextWithOptions(size, false, 0) UIColor.yellow.setStroke() var tree = Tree() tree.move(x: 300, y: 600) tree.draw(n: 7, len: 450, angle: .pi * -0.5, sw: 1) view.layer.contents = UIGraphicsGetImageFromCurrentImageContext()?.cgImage UIGraphicsEndImageContext() let preview = view