Swift Int.randomの連続具合

2019年3月14日

概要

1〜2000のランダム値の連続具合を調べる。

ソース

Playgroundで実行

import Foundation

for _ in 1...20 {
    var select = [Int](repeating:0, count:2000)
    var befor = -1
    for _ in 1...2000 {
        let selectNo = Int.random(in: 1...2000)
        select[selectNo - 1] = select[selectNo - 1] + 1
        if befor == selectNo {
            print("same:\(selectNo)")
        }
        befor = selectNo
    }
    print("0 : \(select.filter({i in i == 0}).count) 2:\(select.filter({i in i == 2}).count) >=3:\(select.filter({i in i >= 3}).count)")
}

連続しても2回、3回続くことはなかった

結果

same:1353
same:1128
same:1163
0 : 751 2:365 >=3:170
same:1816
0 : 734 2:358 >=3:163
same:313
same:644
0 : 742 2:382 >=3:164
same:645
same:1363
0 : 723 2:358 >=3:153
0 : 750 2:352 >=3:166
same:899
0 : 732 2:370 >=3:160
same:1291
same:208
same:1606
0 : 717 2:347 >=3:162
same:1373
0 : 723 2:366 >=3:153
0 : 739 2:385 >=3:157
same:1411
same:332
0 : 749 2:382 >=3:156
same:1399
same:1237
same:1800
0 : 711 2:354 >=3:159
same:258
0 : 730 2:352 >=3:165
same:868
same:192
0 : 728 2:359 >=3:161
0 : 746 2:385 >=3:159
0 : 712 2:359 >=3:159
same:1727
0 : 762 2:377 >=3:167
same:1768
0 : 755 2:360 >=3:171
same:1045
same:273
0 : 746 2:364 >=3:168
same:485
0 : 718 2:364 >=3:156
same:320
same:1779
same:1135
0 : 728 2:350 >=3:166